The constituents of the essential oil from the fruit of Pittosporum undulatum / by Frederick B. Power and Frank Tutin.

  • Power, Frederick B. (Frederick Belding), 1853-1927
Date:
[1906]
Catalogue details

Licence: In copyright

Credit: The constituents of the essential oil from the fruit of Pittosporum undulatum / by Frederick B. Power and Frank Tutin. Source: Wellcome Collection.

    7/14 (page 1087)
    123°, was prepared. The fraction was also examined for camphene, but with a negative result. Fraction 165—169°.—The weight of this fraction was 18 grams. 0-1324 gave 0 4274 C02 and 01401 H20. C = 88*0; H=118. d5°/15° = 0*8494; aD + 73°50' in a 1-dcrn. tube. Fraction 169 —173°.—The weight of this fraction was 27 grams. 0-1352 gave 0-4345 CO, and 0*1428 H20. C = 87‘6 ; H=ll-7. cZ15°/15° = 0-8482; aD + 79°36' in a 1-dcm. tube. Both this fraction and that immediately preceding it were colour¬ less, limpid liquids, and evidently consisted of a mixture of pinene with the constituent of the following fraction. Identification of Limonene. Fraction 173—180°.—This fraction represented by far the largest portion of the oil, and amounted to 485 grams. It was a colourless, highly refractive liquid, having the characteristic odour of limonene, and on analysis was found to consist entirely of a hydro¬ carbon. 0*1140 gave 0*3679 C02 and 0-1214 H20. C = 88’0 ; H = 11 8. C10H16 requires C = 88*2 ; H = 11 *8 per cent. J15°/15° = 0-8488; aD + 89°10' in a 1-dcm. tube. It was leadily identified as cf-limonene by tfie formation of the tetrabromide, which, after iecrystallisation from ethyl acetate, melted at 104°. Fraction 180—185°.—The weight of this fraction was 46 grams. 0T 161 gave 0 3657 C02 and 0*1211 H2C. C = 85-9; H—116. </15°/15° = 0*8588 ; aD + 82°42' in a 1-dcm. tube. This fraction evidently also consisted to a large extent of ^-limonene. Fraction 185—195°.—The weight of this fraction was only 4*8 grams. 0-1083 gave 0*3347 C02 and 0-1128 H20. 0 = 84*3 ; H= 11-6. (/15°/15° = 0*8727 ; aD +6fi°48' in a 1-dcm. tube. It was evidently a mixture of the hydrocarbon contained in the pre¬ ceding fractions with the oxygenated substance contained in the succeeding ones. Fraction 195—205°.—This fraction, which was very pale yellow, amounted to only 4T grams. 0*1251 gave 0*3736 C02 and 0-1293 H20. C = 81*4; H = ll-5. di5°/15° = 0*8938 ; aD + 46°32' in a 1-dcm. tube.